Solve x^2+8x+10=3 by completing the square

x = -1 and x = -7

Step-by-step explanation:

Rewrite x^2+8x+10=3 as  x^2 + 8x +                            10=3

Now identify the coefficient of the x term.

It is 8.  Halve that, getting 4, and then square

this result, getting 16.  

Now add 16 and then subtract 16   in   x^2 + 8x +                       +    10=3, as

follows:                                                    x^2 + 8x +  16      - 16       +   10=3

Simplify this in two ways:  First, rewrite x^2 + 8x +  16 as (x + 4)^2, and

Combine -16 and 10:  -6

and rewrite the equation as                     (x + 4)^2  - 6 = 3

Now add 6 to both sides:                          (x + 4)^2       = 9

Take the square root of both sides:

                                                                    x + 4 = ±3

Then x = -4 + 3 and x = -4 -3,   or   x = -1 and x = -7

Its the 2nd one