Solving the following problem with graphic approach Z max: 60x1+ 50x2
4x1+ 100 x2≤100
2 x1+ x2≤22
3x1+3 x2≤39
X1X2≥0

First, you would do 15 divided by 6, since you want to find out how much one ticket costs. 15 ÷ 6 = 2.5. So, each ticket costs $2.5. Now, you would multiple 2.5 by 9. 2.5 x 9 = 22.5. The chess club members would have to pay $22.50 if all 9 members wanted to go to the tournament.