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ebanzz
12.12.2019 •
Mathematics
Someone just robbed a bank. the police set a triangular perimeter of 16 kilometers where the robber may be hiding. two of the three
coordinates for this triangular perimeter are (2, 2) and (2, -1). each unit represents a kilometer. the area covered is a 12 square kilometers
which of the following is the third coordinate of the triangular perimeter?
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Ответ:
Step-by-step explanation:
Perimeter = 16 km
s = 8 km
Area =![\sqrt{s(s-a)(s-b)(s-c)}](/tpl/images/0414/7261/27832.png)
Area = 12 sq km
Let the third coordinate be (x,y).
Then, a =![\sqrt{(2-2)^{2}+(2-(-1))^{2} }](/tpl/images/0414/7261/e8376.png)
=3
b =![\sqrt{(x-2)^{2}+(y-2)^{2} }](/tpl/images/0414/7261/f2288.png)
c =![\sqrt{(x-2)^{2}+(y-(-1))^{2} }](/tpl/images/0414/7261/89c51.png)
Solving, a+b+c = 16
and using area equation we get
x = -6
y = 2
Ответ:
y+45^79(x+92)
Step-by-step explanation: