SOMEONE PLEASE HELP MEEE HOW DO YOU DO THIS

A. 162 m²

Step-by-step explanation:

==>Given:

Isosceles trapezoid with:

base a = 19m

base b = 35m

Perimeter = 74meters

==>Required:

Area of trapezoid

==>Solution:

Recall: the length of the legs of an isosceles trapezoid are equal.

Perimeter of isosceles trapezoid = sum of the parallel sides + 2(length of a leg of the trapezoid)

Let l = leg of trapezoid.

Perimeter = 74m

Sum of parallel sides = a+b = 19+35 = 54m

Thus,

74 = 54 + 2(l)

74 - 54 = 2(l)

20 = 2(l)

l = 20/2 = 10m

Let's find area:

Area = ½(a+b)*h

a = 19

b = 35

h = ?

Using Pythagorean theorem, let's find h as follows:

h² = l² - [(35-19)/2)²

h² = 10² - [16/2]²

h² = 100 - 64

h² = 36

h = √36 = 6m

Area = ½ x (a+b) × h

= ½ × (19+35) × 6

= ½ × 54 × 6

= 27 × 6

Area = 162m²