Someone ! who is correct? explain your reasoning. alejandra: 2a2b(−2ab3)−2 = (2a2b)(−2ab3)2 = (2a2b)(−2)2a2(b3)2 = (2a2b)22a2b6 = 8a4b7 kyle: 2a2b(−2ab3)−2=2a2b(−2)−2a(b3)−2 = 2a2b(4ab−6) = 2a2bb64a = ab72

Without the use of appropriate symbols and parentheses, it is hard to tell what the problem is. We think you might be trying to simplify
  2·a²b·(-2·ab³)⁻²
  = 2·(-2)⁻²·a²·a⁻²·b·b⁻⁶
  = 2/(4b⁵)
  = 1/(2b⁵)

If so, this would mean neither Alejandra nor Kyle is correct.


First of all, look at the constants. It appears you have a multiplier of 2 at the front, and a multipier of -2 inside parentheses that are raised to the -2 power. The product of these is 2^(1-2) = 1/2. If Kyle's answer is (ab^7)/2, then the constant is correct. As is, Kyle's answer looks like a·b^(72), which is clearly incorrrect.

 y=2

Work:

The equation of a line is y=mx+b, where m represents the slope, b represents the y intercept, and x and y represent a coordinate point on the line. So in this situation, m would be 0, x would be -5, and y would be 2. 

This makes the equation 2=(0)(-5)+b or 2=0+b or 2+=b.

You then have the values of all variables, so you would remove the x and y values to get the final equation which is y=(0)x+2 or y=2.