Mathematics: Steve wants to start his own t-shirt business. his initial costs to get the business going are $1,500. it also costs on average $3 per shirt. steve charges $10 for each shirt he sells. how many shirts does steve need to sell to break-even?

Steve wants to start his own t-shirt business. his

Ответ:

andrew194

27.06.2019

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.

0,0(0 оценок)

Ответ:

wdw52001

08.06.2022

Mathematics

Answer with explanation:

Binomial probability formula to find the probability of getting success in x trials is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where n is the sample size , p is the proportion of getting success in each trial. (1)

Given : A boxcar contains six complex electronic systems. Two of the six are to be randomly selected for thorough testing and then classified as defective or not defective.

i.e. n= 2

a) If three of the six systems are actually defective.

$\Rightarrow\ p=\dfrac{3}{6}=\dfrac{1}{2}$

Then, the probability that at least one of the two systems tested will be defective will be :_

$P(x\geq1)=1-P(x=0)\\\\=1-^{2}C_{0}(\dfrac{1}{2})^0(\dfrac{1}{2})^{2} \ \ \text{[By using formula (1)]}\\\\=1-(\dfrac{1}{2})^2\ \ \because\ ^nC_0=1\\\\=1-\dfrac{1}{4}=\dfrac{3}{4}$

Hence, the probability that at least one of the two systems tested will be defective = $\dfrac{3}{4}$

b) If four of the six systems are actually defective.

$\Rightarrow\ p=\dfrac{4}{6}=\dfrac{2}{3}$

Then, the probability that at least one of the two systems tested will be defective will be :_

$P(x\geq1)=1-P(x=0)\\\\=1-^{2}C_{0}(\dfrac{2}{3})^0(1-\dfrac{2}{3})^{2} \ \ \text{[By using formula (1)]}\\\\=1-(\dfrac{1}{3})^2\ \ \because\ ^nC_0=1\\\\=1-\dfrac{1}{9}=\dfrac{8}{9}$

Hence, the probability that at least one of the two systems tested will be defective = $\dfrac{8}{9}$

The probability that both are defective :

$P(x=2)=^{2}C_{2}(\dfrac{2}{3})^2(1-\dfrac{2}{3})^{0} \ \ \text{[By using formula (1)]}\\\\=(\dfrac{2}{3})^2\ \ \because\ ^nC_n=1\\\\=\dfrac{4}{9}$

Hence, the probability that both are defective = $\dfrac{4}{9}$

0,0(0 оценок)

Steve wants to start his own t-shirt business. his initial costs to get the business going are $1,500. it also costs on average $3 per shirt. steve charges $10 for each shirt he sells. how many shirts does steve need to sell to break-even?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question