Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation to find the probability that all five tetrahedrons land on 3. how do i do this? i don't understand

The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:
1/4(1/4)(1/4)(1/4)(1/4) = 1/1024

The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:

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2.    4.88 feet

Step-by-step explanation:

cos∅ = adj/hyp

cos71 = adj/15

adj = 15*cos71

adj = 4.88