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sydthekid25
15.07.2019 •
Mathematics
Suma a doua numere este 24 de intregi 3 pe 8.aflati numerele stiiind ca unul dintre ele este mai mare decat celalalt cu 3 intregi 5 pe 6
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Ответ:
The sum of two numbers is 24 whole 3 by 8.Lay the numbers knowing that one of them is bigger than the other with 3 whole 5 on 6.
Let the two numbers be x and y. Then x+y=24 3/8. Let x be the larger number. Then x = y+ 3 5/6.
Solve these two equations for x and y. Solve the first equation for x, obtaining x = (24 3/8) - y. Subst. this into the 2nd equation, we get
24 3/8 - y = y + 3 5/6, so 24 3/8 - (3 5/6) = 2y = 20.542, so y = 10.27. Since x = y + 3 5/6, x = 10.27 + 3 5/6 = 14.104
Solution: (10.27, 14.10)
Ответ:
x(t)=![2-2e^{-t}-2te^{-t}](/tpl/images/0329/3063/ff450.png)
Step-by-step explanation:
The function x(s) = (2)/(s(s+1)^2) can be expressed as partial fractions:
X(s)=![\frac{2}{s(s+1)^2}=\frac{A}{s}+\frac{B}{s+1}+\frac{C}{(s+1)^2}](/tpl/images/0329/3063/55d50.png)
2=A·(s+1)²+B·s·(s+1)+C·s
2=A·(s²+2s+1)+B·(s²+s)+C·s
2=A·s²+2sA+A+B·s²+Bs+C·s
2=s²(A+B)+s(2A+B+C)+A
So we can find the values of A, B and C by solving these equations:
A+B=0 ⇒ 2+B=0 ⇒ B= -2
2A+B+C=0 ⇒ 2·2+(-2)+C=0 ⇒ C= -2
A=2
So X(s) is expressed as:
X(s)=![\frac{2}{s}+\frac{-2}{s+1}+\frac{-2}{(s+1)^2}](/tpl/images/0329/3063/a47df.png)
Using the inverse laplace transform tables we obtain x(t):
ℒ⁻¹{X(s)}=ℒ⁻¹{
}
ℒ⁻¹{X(s)}=ℒ⁻¹{
}+ℒ⁻¹{
}+ℒ⁻¹{
}
x(t)=![2-2e^{-t}-2te^{-t}](/tpl/images/0329/3063/ff450.png)