Suppose a deck of cards contains 13 cards: 5 green cards numbered 1-5, 4 red cards numbered 1-4, and 4 blue cards numbered 1-4.
For 3.1-3.3, 5 draws are made without replacement. X is the number of green cards drawn and Y is the number of red cards drawn. Z is the sum of the numbers on the tickets.
G1 = first card is green
G2 = second card is green
Enter the probability as a fraction.
P(at least one green) = .

Step-by-step explanation:

Given

Solving (a):

This is calculated as:

Solving (b):

This is calculated as:

-- this is so because the selection is without replacement

Solving (c):

Using the complement rule, we have:

To calculate , we have:

--- Green

---- Not green

The probability that both selections are not green is:

So, we have:

Simplify

Recall that:

Take LCM

A-Triangle

B- Quadrilateral

C- Triangle

D- Quadrilateral

E- Quadrilateral

F-Triangle

G-Triangle

H-Quadrilateral

I- Triangle

J-Triangle

Step-by-step explanation:

If it has 3 sides it’s a triangle, if it has 4 it’s a quadrilateral.