Suppose a (the word 'a' means starting amount is 1) radioactive substance decays at a rate of 5% per hour, what percent of the substance is left after 10 hours? (make sure you convert your answer from decimal to percent and round to the nearest whole percent)

The percentage of the substance is left after 10 hours is 60%.

Step-by-step explanation:

The expression representing the amount left after a certain period of decay is:

Here,

y = final amount

a = initial amount

r = decay rate

t = time taken

It is provided that:

a = 1

r = 5% / hour

t = 10 hours

Compute the percentage of the substance is left after 10 hours as follows:

 

The percentage is: 0.60 × 100 = 60%.

Thus, the percentage of the substance is left after 10 hours is 60%.

hello 

so the problem is 6x+3y=-12y=-2x+4 
you can bring -2x-6x=
(remember the integer rule if two negative you add NOT subtract and keep the sign)
-2x-6x=-8x 
-8x+3y=-12y+4
now take 3y=subtract 12y
-12y-3y=-15y

-8x=-15y+4
no solution cause not same variable but not sure 
have a wonderful Wednesday
can I get brainlest plz