Suppose EG=3, EB=8, A(F)=7, m∠EBG=23, m∠EGF=32, and m∠CAE=51. Find m∠CAF. *ignore the parenthesis it won't allow a post without them.

m∠CAF is 28°

Step-by-step explanation:

The given parameters are;

EG = 3, EB = 8, A_F = 7, m∠EBG = 23°, ∠EGF 32°, and m∠CAE = 51°

From the diagram, we have;

m∠EBG = m∠EAD ;                                                    Given

Therefore, m∠EAD = 23°  

m∠CAE = m∠CAF + m∠EAD                                     Angle addition postulate

Therefore, we have;

51° = m∠CAF + 23°                        

m∠CAF = 51° - 23°                                          

m∠CAF = 28°

not sure

Step-by-step explanation:

had to earn point