Mathematics: Suppose that a and b are independent events. if p(a)=.4 and p(b)=.1, what is p(a∩b¹)? a .54 b .06 c .36 d .04

Suppose that a and b are independent events. if p(a)=.4

Ответ:

graymonky12

11.03.2022

ANSWER

$P(A \cap B')=0.36$

EXPLANATION

If event A and event B are independent, then

$P(A \cap B)= P(A ) \times P(B)$

otherwise A and B are dependent events.

We were given that,

P(A) = 0.4

and

and we were asked to evaluate

$P(A \cap B')$

Since A and B are independent,

$P(A \cap B') = P(A ) \times P(B')$
Recall that,

P(B') = 1 - P( B)

This implies that,

$P(A \cap B') = P(A ) \times (1 - P(B) )$

We now substitute the above values to obtain,

$P(A \cap B') = 0.4 \times (1 - 0.1 )$

$P(A \cap B') = 0.4 \times 0.9$

$P(A \cap B') = 0.36$

Therefore the correct answer is C.

0,0(0 оценок)

Ответ:

javier1026

24.11.2022

Mathematics

how old are you bro?!

Step-by-step explanation:

idk what to put

0,0(0 оценок)

Suppose that a and b are independent events. if p(a)=.4 and p(b)=.1, what is p(a∩b¹)? a .54 b .06 c .36 d .04

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