gabby0148
26.08.2020 •
Mathematics
Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the random variable X as the number of defective cameras in the sample.
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Ответ:
a.
The probability of X
k P(X=k)
0 0.25
1 0.5
2 0.25
b. The expected variable value of X; E(X) = 1
Step-by-step explanation:
Given that:
number of cameras = 6
numbers of defective = 3
the probability of defective camera p = 3/6 = 0.5
sample size n = 2
Then X = {0,1,2}
Suppose X is the given variable that represents the number of defective cameras in the sample.
∴
X Bin (n =2, p = 0.5)
The probability mass function of binomial distribution can be computed as :
For ;
x = 0
The probability P(X=0)
For :
x = 1
The probability P(X=1)
For :
x = 2
The probability P(X=2)
The probability of X
k P(X=k)
0 0.25
1 0.5
2 0.25
The expected variable value of X can be computed as:
E(X) = np
E(X) = 2 × 0.5
E(X) = 1
Ответ:
2 8/942
Step-by-step explanation:
5!2#5¢{}×%✓=ππ~w