Suppose that AKL M is isosceles with base MK. Suppose also that m 2 M= (3x+36) and m 2 K = (4x +31)
Find the degree measure of each angle in the triangle.
m ZK = 0
m 2L =
m ZM =
MA
K
(3x +36)
(4x +31).
Х

m<K = 51°

m<L = 78°

m<M = 51°

Step-by-step explanation:

Base angles of an isosceles ∆ are equal to each other, therefore,

m<M = m<K

Substitute

3x + 36 = 4x + 31

Collect like terms and solve for x

3x - 4x = -36 + 31

-x = -5

Divide both sides by -1

x = 5

Let's find each degree measure using the value of x

m<K = 4x + 31

Plug in the value of x

m<K = 4(5) + 31

m<K = 20 + 31

m<K = 51°

m<M = 3x + 36

= 3(5) + 36

= 15 + 36

m<M = 51°

m<L = 180° - (m<M + m<K) (sum of triangle theorem)

Substitute

m<L = 180 - (51 + 51)

m<L = 78°

134 degrees

Step-by-step explanation:

These are known as supplementary angles, or two angles that add up to 180 degrees. We know they add up to 180 degrees because they both lie upon the same straight line.

Using this information, we can take:

180 = 46 + w

134 = w

134 degrees