Suppose that sinθ=8/17 and θ is in the second quadrant. find sin(2θ), cos(2θ), and tan(2θ) exactly.

sin(2Θ) = 2cosΘsinΘ
sinΘ=opposite/hypotenuse=8/17
adjacent = (17^2 - 8^2)^1/2 =15
sin(2Θ) = 2cosΘsinΘ = 2 *(15/17)*(8/17)= 240/289
opposite of 2Θ equals 240
hypotenuse of 2Θ equals 289
adjacent of 2Θ = (289^2 - 240^2)^1/2 = 161
cos(2Θ) = 161/289
 tan(2Θ) = 240/161

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