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olivasm5626
20.12.2019 •
Mathematics
Suppose that surface σσ is parameterized by r(u,v)=⟨ucos(6v),usin(6v),v⟩r(u,v)=⟨ucos(6v),usin(6v),v⟩, 0≤u≤70≤u≤7 and 0≤v≤1π30≤v≤1π3 and f(x,y,z)=x2+y2+z2f(x,y,z)=x2+y2+z2. set up the surface integral (you don't need to evaluate it). ∫σ∫f(x,y,z)ds=∫r∫f(x(u,v),y(u,v),z(u,v))∥∥∥∂r∂u×∂r∂v∥∥∥da∫σ∫f(x,y,z)ds=∫r∫f(x(u,v),y(u,v),z(u,v))‖∂r∂u×∂r∂v‖da
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Ответ:
y=1/2x
Yes, this is linear