Suppose that the log-ons to a computer network follow a poisson process with an average of 2 counts per minute. (a) what is the mean time between counts (in minutes)? (round yours answers to 3 decimal places.) (b) what is the standard deviation between counts (in minutes)? (round yours answers to 3 decimal places.) (c) let x denote the time between two counts. if it is an average of 3 counts per minute, find the value of x such that p(x

H0 : μ = 60000

H1 : μ ≠ 60000

Test statistic = 3.464

Step-by-step explanation:

Given :

Sample mean salary, xbar = 80000

Sample standard deviation, s = 10000

Population mean salary , μ = 60000

Sample size, n = 3

Hypothesis :

H0 : μ = 60000

H1 : μ ≠ 60000

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (80000 - 60000) ÷ (10000/√(3))

T = 20000 / 5773.5026

T = 3.464

The Decison region :

If Tstatistic >Tcritical

Tcritical at 10%, df = 2 ; two - tailed = 2.9199

Tstatistic > Tcritical ; He