Suppose that you 2 two dice and observe the numbers showing on the uppermost surfaces of the dice. What is the probability that the sum is less than 5

The required probability (P) =  1/6

Step-by-step explanation:

From the given information:

Suppose two dice are observed; Then the number of outcomes in first dice = 6 i.e (1,2,3,4,5,6) and also the number of outcomes in second dice = 6 as well i.e (1,2,3,4,5,6)

The total number of outcomes of two dices = 6×6 = 36

Now for a sum that is less than 5; their outcomes are [(1,1) ,(1,2) , (1,3) ], [(2,1), (2,2) ], (3,1) = 6 outomes

The total number of outcomes for the sum that is less than 5 = 6

∴

The required probability (P) = Total number of outcomes for the sum that is less than 5 / Total number of outcomes of two dices

The required probability (P) = 6/36

The required probability (P) = 1/6

5 hundredths

5/100

Step-by-step explanation: