Suppose the base and height of a triangle sum to 18 cm, and the area of the triangle is 36 square cm. if the base is larger than the height, what are the dimensions (base and height) of the triangle

15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:

a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)

Ok so the end equation here is going to be VCy-VCo=
air space. So we need to find the volume of the cone and the volume of the cylinder.

Lets start with the volume of the cylinder since its easiest. The volume of a cylinder is Pi*r^2*h = Volume.
We already know that the radius is 5 and the height is 16 so lets plug them in and solve. 3.14*5^2*16=1,256

Now lets solve to find the volume of the cone. Now this ones a bit harder, the equation is: Pi*r^2*(h/3)= Volume.
The radius is 4 and the height is 12, so now just solve! 3.14*4^2*(12/3)=201

Now we just need to subtract the Volume of the cylinder from the volume of the cone. 1,256-201=1,055

If you have any questions just ask!