rachelsweeney10
08.04.2020 •
Mathematics
Suppose the circle with equation (x-2)2 +(y+4)2 = 7 is translated by (x, y)➡️(x + 3,y - 1). What is the equation of the image of the
circle? Explain.
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Ответ:
The answer to your question is (x - 5)² + (y + 5)² = 7
Step-by-step explanation:
Data
Circle equation (x - 2)² + (y + 4)² = 7
translated (x,y) (x + 3, y - 1)
Process
1.- Find the center of the circle
Remember that the center is represented as (h, k)
From the standard equation
(x - 2)² + (y + 4)² = 7
h = 2
k = -4
Center = (2, -4)
This is the point that is going to change its position
2.- Determine the new coordinates of the center
New center = (2 + 3, -4 - 1)
= (5, -5)
3.- Find the new equation of the circle
(x - 5)² + (y + 5)² = 7
Ответ:
The y-intercept of AB is (4/3) and the equation of BC is y = (-1/6) x + (4/3)
If the y-coordinate of point C is 13, its x-coordinate is 4.
=====================================
Step-by-step explanation:
AB and BC form a right angle at their point of intersection, B.
So, AB ⊥ BC
A = (14 , -1) , B = (2,1)
Part A: Find the y-intercept of AB.
The general equation of the line y = mx + c
Where: m is the slope and c is constant represents y-intercept.
m = (y₂ - y₁)/(x₂ - x₁)
m =
y = (-1/6) x + c
Substitute with the point (2,1) to find c
1 = (-1/6) * 2 + c
c = 1 + 2 *(1/6) = 4/3
y = (-1/6) x + 4/3
So, the y-intercept of AB is 4/3
=======================================
Part B: Find the equation of BC.
BC ⊥ AB at point B
if m is the slope of AB, the slope of BC = (-1/m)
m = (-1/6)
So, the slope of BC = (-1/m) = 6
The equation of the line BC ⇒ y = 6x + c
Substitute with the point (2,1) to find c
1 = 6 * 2 + c
c = 1 - 12 = -11
y = 6x - 11
=========================================
Part C: Find x-coordinate of C if y-coordinate of point C is 13.
The equation of the BC is y = 6x - 11
Substitute with the y-coordinate of point C = 13
13 = 6x - 11
6x = 13 + 11 = 24
x = 24/6 = 4