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Jamie228
05.11.2020 •
Mathematics
Suppose the fish population in a local lake increases at a rate proportional to the population each moment. there were 1000 fish 5 years ago and 2000 fish 4 years ago. How many fish are there right now?
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Ответ:
6000
Step-by-step explanation:
If the fish population in a local lake increases at a rate proportional to the population each moment, this can be expressed as;
P = k/t (the scenario is an inverse proportionality because as the time is reducing, the population is increasing by the same factor)
If there are 1000 fish 5 years ago and there are 2000 fish 4 years ago
Yearly percentage increase will be;
2000-1000/1000 × 100%
1000/1000×100%
= 100%
This means that the population increases by 100% on a yearly basis (by a factor of 1000)
The population 3 years ago will be population
P = 2000+1000
P = 3000
The population 2 years ago will be population
P = 3000+1000
P = 4000
The population 1 year ago will be population
P = 4000+1000
P = 5000
The population now will be population
P = 5000+1000
P = 6000 populations
Ответ:
There is enough statistical evidence to suggest that there is no difference between the mean number of households picking either service
Step-by-step explanation:
The parameters of the music streaming service are;
The average number of households using Apple Music,
= 1.73 million
The standard deviation, σ₁² = 0.46 million
The average number of households using Spotify,
= 2.17 million
The standard deviation, σ₂² = 0.33 million
The significance level = 0.01
Hypothesis testing with different population standard deviation
H₀:
≠ ![\overline {X}_2](/tpl/images/1170/7501/283f3.png)
H₁:
= ![\overline {X}_2](/tpl/images/1170/7501/283f3.png)
p-value for the test statistic = 2 × P(Z <-2.6923) = 2 × 0.00357 = 0.00714
Therefore, the p-value is less than the significance level, and it is therefore unlikely that the result will be observed under the null hypothesis
We therefore reject the null hypothesis and there is enough statistical evidence to suggest that there is no difference between the mean number of households picking either service