thebestandrew922
23.10.2019 •
Mathematics
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. assume that the cost of materials for the base is$$12 dollars per square meter, and the cost of materials for the sides is $$8 dollars per square meter. the height of the box is three times the width of the base. what’s the least amount of money we can spend to build such a container?
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Ответ:
265.25
Step-by-step explanation:
Given
Volume of box
height is 3 times the width
let height, length and breadth be H, L & B
4=B^2\times L[/tex]
Cost of side walls $
Cost of base $
Cost of side walls
Cost of base
Total cost
differentiate C w.r.t B to get minimum cost
L=2.19 m
C=$ 265.25
Ответ:
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Explanation: