Suppose you drop a ball from 120 feet. The ball will bounce to 25 of its previous height. What is the total distance the ball travels from when you let it go to the max height it reaches after the 5th bounce? Round to the nearest tenth. A) 268.7
B)273.9
C)277.1
D)279.3

277.1 feets

Step-by-step explanation:

Drop height = 120 feets

Ball bounces 2/5 of previous height

Height after 1st bounce :

120 * 2/5 = 48 feets

Return distance = 48 feets

Height after second bounce :

48 * (2/5) = 19.2 feets

Return distance = 19.2 feets

Height after 3rd bounce :

19.2 * (2/5) = 7.68 feets

Return distance = 7.68 feets

Height after 4th bounce :

7.68 * (2/5) = 3.072 feets

Return distance = 3.072 feets

Height after 5th bounce :

3.072 * (2/5) = 1.2288 feets

(120 + (2*48) + (2*19.2) + (2*7.68) + (2*3.072) + 1.2288) = 277.1328

= 277.1 feets

Step-by-step explanation:

Given : Expression

To find : The simplest form of the expression

Solution :

We solve the expression step by step :

Step 1- Write the expression

Step 2- Substitute the

Step 3- Taking cube outside

Step 4- 3 will cancel out

Therefore, The simplest form of given expression is