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manillasoccer
04.08.2021 •
Mathematics
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Ответ:
Option B
The probability of one of the coins landing on tails and two of them landing on heads is![\frac{3}{8}](/tpl/images/0446/0316/95a07.png)
Solution:
To find: probability of one of the coins landing on tails and two of them landing on heads
The probability of an event is given as:
The outcomes are given as:
(H, H, H), (H, H, T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H), (T, T, T)
Here, total number of possible outcomes = 8
Favorable outcomes = one of the coins landing on tails and two of them landing on heads
Favorable outcomes = (H, H, T) , (H, T, H) , (T, H, H)
Therefore, number of favorable outcome = 3
Thus probability is given as:
Thus option B is correct