[tex](1 + 0.12 \div 12) { 12 \times 1 \div 2} - - id10121212121844354, kvngsavage156

Ответ:

Hruai

12.03.2022

The answer is:
________________________________________________________
" $\frac{4829}{900}$ "; or, "5 $\frac{329}{900}$ " ;
or, write as: "5.366" .
________________________________________________________
Explanation:
__________________________________
Given: " (1 + 0.12 ÷ 12)12 * 1 ÷ 2− 1 ÷ 0.12 ÷ 12 = ? " ;
___________________________________________

First, start with the "parentheses" ;
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"(1 + 0.12 ÷ 12) = ??

Start with the division: " 0.12 ÷ 12 = 0.01 " .

"(1 + 0.01)" = (1.01) .

We have: "1.01 (12)
Given: " (1.01)12 * 1 ÷ 2 − 1 ÷ 0.12 ÷ 12 = ? " ;

So, 1.01 * 12 = 12 .12 .
______________________
" 12.12 * 1 ÷  2 − 1 ÷ 0.12 ÷ 12 = ? " ;

Note: Using order of operations, treat this problem as:

" [ (12.12 * 1) ÷  2 ] − [ (1 ÷ 0.12) ÷ 12 ] = ? " ;

→ ( 12.12 ÷ 2 ) − (25/3) ÷ 12 ] = ? " ;

→ ( 6.06) − { (25/3) * 1/12) } = ?

→ ( 6.06) − { ( 25* 1) / (3*12) = ?

→ ( 6.06) − { ( 25* 1) / (3*12) = ?

→ ( 6.06) − (25/36) ;

→ 6 $\frac{6}{100}$ − $\frac{25}{36}$   ;

→ 6 $\frac{3}{50}$ − $\frac{25}{36}$   ;

Rewrite " 6 $\frac{3}{50}$ " ; as an improper fraction:

→ " 6 $\frac{3}{50}$ " = "[ (50*6) + 3 ] / 50 = $\frac{303}{50}$ ;
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→ 6 $\frac{3}{50}$ − $\frac{25}{36}$ ;

= $\frac{303}{50}$   − $\frac{25}{36}$ ;

= $\frac{(303*36)-(25*50)}{50*36} = \frac{10,908-1250}{1800}$ ;

= $\frac{9658}{1800}$ ;
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→ Divide EACH SIDE of the "fraction" by "2" ; to simplify:
____________________________________________________
→ $\frac{9658/2}{1800/2}$ ;
= $\frac{4829}{900}$ = 5 $\frac{329}{900}$ ; or, write as:

(5 + (329 ÷ 900) = → 5.3655555555555556 .
→ round to: 5.366 .
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Ответ:

ayoismeisjjjjuan

28.06.2020

Mathematics

9514 1404 393

$129,992

Step-by-step explanation:

The sum of a geometric series is given by ...

Sn = a1·(r^n -1)/(r -1)

Here, the first term is 24000, and the growth factor r is 1+4% = 1.04. The sum is then ...

S5 = 24000·(1.04^5 -1)/(1.04 -1) ≈ 129992

The total earned over 5 years was $129,992.

___

A spreadsheet can list the annual salaries and add them up. The salary each year is 1.04 times that of the previous year. That is shown in the attachment.

Alexander was offered a job that paid a salary of $24,000 in its first year. The salary was set to i

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$(1 + 0.12 \div 12) { 12 \times 1 \div 2} - 1 \div 0.12 \div 12 =$

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