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Crxymia
07.12.2019 •
Mathematics
The amount of $15,000 is invested in two funds paying 2% and 5% simple interest. if the annual interest is $540, how much of the $15,000 is invested in each interest rate?
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Ответ:
The amount $15000 is divided as
in 2% = $7000
in 5% = $8000
Step-by-step explanation:
It is given that the total amount is $15000 and rates of interests are 2% and 5%.
Let the amount invested in 2% be "x", so the amount invested in 5% is (15000 - x).
The annual interest on x part is given as,
=![(\frac{2}{100})(x)](/tpl/images/0407/4910/a938b.png)
Similarly, The annual interest on (15000 - x) part is given as,
=![(\frac{5}{100})(15000 - x)](/tpl/images/0407/4910/dbc3f.png)
the total annual interest is given as $540
Thus, 540 =![(\frac{5}{100})(15000 - x) + (\frac{2}{100})(x)](/tpl/images/0407/4910/ec506.png)
54000 =![2(x) + 75000 - 5(x)](/tpl/images/0407/4910/f505a.png)
21000 = 3(x)
x =
= 7000
Thus the shares are $7000 and (15000 - 7000) $8000 .
Ответ: