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cluchmasters5634
09.07.2021 •
Mathematics
The amount of snowfall falling in a certain mountain range is normally distributed with a average of 170 inches, and a standard deviation of 20 inches. What is the probability a randomly selected year will have an average snofall above 200 inches
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Ответ:
0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a average of 170 inches, and a standard deviation of 20 inches.
This means that![\mu = 170, \sigma = 20](/tpl/images/1391/6052/a099a.png)
What is the probability a randomly selected year will have an average snowfall above 200 inches?
This is 1 subtracted by the p-value of Z when X = 200. So
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.
Ответ:
A, C, D, on Edge 2020
Step-by-step explanation: