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26.03.2020 •
Mathematics
The amount y ( in grams) of a radioactive isotope phosphorus-32 remaining after t days is y=a(0.5)^t/14, where a is the initial amount (in grams) what percent of the phosphorus-32 decays each day
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Ответ:
Step-by-step explanation:
The way I figured this out is to just pick some starting values for the grams of this element and plug them into the formula using t = 1 day and seeing how much is left. I chose 2 different starting amounts and came up with the same percentage each time, so it must be correct! Here's what I did:
First I chose a starting amount, a, of 10 grams. Plugging into the formula:
and got that the amount LEFT was 9.5 grams
Then I chose a starting amount, a, of 20 grams. Plugging into the formula:
and got that the amount LEFT was 19 grams.
I then asked the algebraic question,"What percent of 10 is 9.5?" which translates to
x% * 10 = 9.5 and
x = 95% (that's the amount left as a percentage).
and
x% * 20 = 19 and
x = 95%
Since both of those came out the same, that tells me that after 1 day there is still 95% of the element remaining, so 5% decays each day.
Ответ:
so common factor = 81/27 = 3 , m^5/m^3 = m^2 , n^2/n = n
common factor = 3m^2n (B)