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msalecora
12.08.2020 •
Mathematics
The angle measurements in the diagram are represented by the following expressions. \qquad \blueD{\angle A} = \blueD{8x +6 ^\circ}∠A=8x+6 ∘ start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 8, x, plus, 6, degrees, end color #11accd \qquad \green{\angle B} = \green{4x +38^\circ}∠B=4x+38 ∘
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Ответ:
The reason why is...
3x^6y^2 + 81y^2 = 3y^2(x^6 + 27)
3x^6y^2 + 81y^2 = 3y^2((x^2)^3 + 3^3)
3x^6y^2 + 81y^2 = 3y^2(x^2 + 3)((x^2)^2 - (x^2)*3 + 3^2)
3x^6y^2 + 81y^2 = 3y^2(x^2 + 3)(x^4 - 3x^2 + 9)