The area of a square is 18 sq in less than twice the area of a triangle. the base of the triangle is 3 in longer and the altitude is the same length as the side of the square

Let the side of the square = x

So, the altitude of the triangle = x
and it's base = x+3

2 (area of triangle) - 18 = area of the square

area of the triangle = (1/2)height× base
and
area of the square = side^2

{ (2)(1/2)(x)(x+3)} -18 = x^2
x^2 + 3 x -18 = x^2
3x -18 =0
3x = 18
x = 6

so, the length of one side of the square = 6 units = altitude of the triangle
and the base of the triangle = 6+ 3 = 9cm.

1. A
2. B
3. B
4. D=11
5. 25, 20,

By order of operations, the answer above which is marked brainliest is incorrect