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gtrsoccer
16.07.2021 •
Mathematics
The average electric bill for a small electric company is $72 for the month of April with a standard deviation of $6. If the amounts of the bills are normally distributed, find the probability that the mean of the bills for 15 randomly selected residents will be less than $75
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Ответ:
Hence the probability that the mean of their utility bills will be less than $75 = P(X < 75) is 0.9736.
Step-by-step explanation:
Now,
Population mean electric bill,
$72
Population standard deviation,
$6
Standard error of the mean![= \sigma / \sqrt{n} = 6 / \sqrt{15} = 1.5492](/tpl/images/1394/9386/cf383.png)
The probability that the mean of their utility bills will be less than $75 = P(X < 75)
= P[Z < (75 - 72) / 1.5492]
= P[Z < 1.9365]
= 0.9736 (Using Z table)
Ответ:
i'll keep this short for those who just want the systematic sampling.
Step-by-step explanation: