The average salary of a travel management professional is $98,500. Assume that the standard deviation of such salaries is $40,000. A random sample of 100 travel management professionals are selected, then the mean and standard deviation of the sampling mean is .
a) 98500 and 400
b) 9850 and 400
c) 9850 and 4000
d) 98500 and 4000

c) 9850 and 4000

Step-by-step explanation:

Formula for calculating the standard deviation of the sampling mean = standard deviation/√n

Where n is the total number of sample = 100

Standard deviation of salaries = $40,000

Standard deviation of sampling mean = $40,000/√100

= $40,000/10

= $4,000

Similarly, mean deviation of the sampling mean = average salary/√n

Mean deviation of sampling mean = $98,500/√100

= $98,500/10

= $9,850

4

Step-by-step explanation:

Here we need to estimated quotient of -23.514 and -3.98.

We need to use the division to find the answer.

Before going to the division, we need to estimate the dividend -23.514 and the divisor -3.98 to nearest integer.

-23.514, here the tenths place digit is 5, since it is greater than or equal to 5, we can 1 in the unit place and round off.

So, -23.514 = -24

-3.98, here the tenths place digit is 9 which is greater than or equal to 5, so we add 1 in the unit place and estimate.

So, -3.98 = -4

Now we have to divide -24 by -4.

Remember, when divide a negative by a negative number, the answer will be in positive. This is a division sign rule.