The average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. Some of the weights of the fish are shown in the table. What was the weight of the heaviest fish?

14.6

Step-by-step explanation:

It is given that,

The average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. From the attached figure, the weight of 5 fish are given. We need to find the weight of Wayne S. fish.

Average = sum of terms/no of terms

Let the weight of Wayne S. is x. So,

Here the sum of terms is x+12.8+12.6+11.8+9.7 and the number of terms is 5.

So, the weight of the heaviest fish is 14.6.

A and C are the answers on Edgen.

Step-by-step explanation:

(A) 3(m) = 45,000

(C) m = (1/3)(45,000)