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14.12.2020 •
Mathematics
The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find the z-score thay correspondes to a lifespan of 2470 hours. A. 2.5 B.1.5 C.-1.5 D-2.4
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Ответ:
C.-1.5
Step-by-step explanation:
Given: The burning time of a very large candle is normally distributed with mean
of 2500 hours and standard deviation
of 20 hours.
Let X be a random variable that represent the burning time of a very large candle.
Formula:![Z=\dfrac{X-\mu}{\sigma}](/tpl/images/0980/5256/19e7a.png)
For X = 2470
So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5
Hence, the correct option is C.-1.5.
Ответ: