The circle below is centered at the origin and has a radius of 7. What is its equation?
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O A. x²-7=7
B. x2 + y2 = 49
c. x2 - y2 = 49
D. x² + 7 = 7

HELPPP ASAPPP

x^2 +y^2 = 49

Step-by-step explanation:

The equation for a circle is

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center of the circle and r is the radius

( x-0)^2 + (y-0)^2 = 7^2

x^2 +y^2 = 49

we use the following formula to calculate height, 'h', under the effect of gravity: 

h = vt - (1/2)gt^2, where g = 9.8m/s^2 and 't' represents time in seconds

8 ft/s * 0.3048 = 2.4384 m/s

we treat mass as inconsequential to the problem, considering only the effect of initial velocity and gravitational pull

to find his 'hang time' we solve for h=0, knowing that t=0 will be the first value (before the jump): 

0 = 8(0.3048)t - (9.8/2)t^2

solving for 't' we have t=0.497

the 'hang time' will be approximately 0.5 seconds, or 1/2 of a second

the maximum height will be 0.2488m, or 0.816 feet, or 9.8 inches

on the moon, the hang time and height will increase by a factor of 6

hang time: approximately 3 seconds on the moon

maximum height: approximately 2.4 feet