bettinger6525
28.01.2020 •
Mathematics
The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14. what is the value of h in this equation? ?
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Ответ:
gropu x terms
x^2-4x
take 1/2 of linear coefient and square it
-4/2=-2, (-2)^2=4
x^2-4x+4
factor
(x-2)^2
h=2
Ответ:
H=2
Step-by-step explanation:
we just need to complete the square for the x terms
gropu x terms
x^2-4x
take 1/2 of linear coefient and square it
-4/2=-2, (-2)^2=4
x^2-4x+4
factor
(x-2)^2
h=2
Ответ:
1. Vertical shift, when k is outside of the parenthesis it indicates the translation up or down. Positive k is up and negative k is down.
2. Horizontal shift, when k is inside of the parenthesis it indicates the translation left or right. BE CAREFUL: positive k is left and negative k is right. Don’t get these mixed up