The combined area of two squares is 17 square meters.

Ответ:

normarjohnson

12.03.2022

we are given that ,

Area of square= (side)^2

Let the side length of smaller square be x

The size of the larger Square are four times as long as the size of the smaller square

$Area \ of \ smaller \ square \ =x^2$

So Area of larger square= 4x^2

The combined Area is 17 square meter.

$x^2+4x^2=17\\\\5x^2=17\\\\x=\sqrt{\frac{17}{5}}$

Hence the smaller square has the side length= $\sqrt{\frac{17}{5}}$

So the larger square has side length= $2\sqrt{\frac{17}{5}}$

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ruslffdr

22.06.2022

-2x -y = -4

Step-by-step explanation:

the formula for calculating the equation of the line passing through two points is (look at the photo)

3 is x1, -2 is y1, -1 is x2 and 6 is y2

solve: x-3/-1-3 = y-(-2)/6-(-2)

x-3/-4 = y+2/8

transport the second fraction to the left of the equal, then it becomes negative:

x-3/-4 - y+2/8 = 0

do the mcm: -2(x-3)-(y+2) = 0

solve (minus in front of a parenthesis changes all signs inside it): -2x+6-y-2 = 0

-2x+4-y = 0

move the unknowns to the left of the equal:

-2x -y = -4

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