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Angellopezzz
28.10.2019 •
Mathematics
The curve y= (1-x)/(x-3) is concave up when:
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Ответ:
y" = [-(x-3)-(1-x)]/(x-3)^2 = 2/(x-3)^2
y" = -4/(x-3)^3
-4/(x-3)^3 > 0
(x-3)^3 < 0
x-3 < 0
x< 3
hope this help
Ответ:
Step-by-step explanation:
The given function is
To find where the function is concave up, we have to find the second derivative of the function.
The derivative of a fraction is
Where
and
.
Using the property, we have
Then, we repeat the process to find the secon derivative
For a concave up inflection, we must evalute![y''0](/tpl/images/0349/4974/73fc3.png)
Therefore, the curve is concave up when
.
In the image attached you can observe this behaviour.
Ответ:
idk
Step-by-step explanation: