The data set represents a progression of hourly temperature measurements use the regression equation y=-0.875x^2 - 3.596x + 20.179 to predict the temperature during the sixth hour

The data set represents a progression of hourly temperature measurements use the regression equatio

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Ответ:

jacobbecker99

16.03.2022

Mathematics

Step-by-step explanation:

A( -4 , -8) ; B( 11 , 5)

$a) AB = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{2})^{2}}\\\\=\sqrt{(11-[-4])^{2}+(5-[-8])^{2}}\\\\=\sqrt{(11+4)^{2}+(5+8)^{2}}}\\\\=\sqrt{15^{2}+13^{2}}\\\\\=\sqrt{225+169}\\\\=\sqrt{394}\\\\$

$Midpoint(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2})\\=(\dfrac{-4+11}{2},\dfrac{-8+5}{2})\\\\$

$=(\dfrac{7}{2},\dfrac{-3}{2})$

= (3.5 , - 1.5)

c) m : n = 3 : 7

$\left ( \dfrac{mx_{2}+nx_{1}}{m+n} , \dfrac{my_{2}+ny_{1}}{m+n} \right )\\\\= \left ( \dfrac{11*3+(-4)*7}{3+7}, \dfrac{5*3+(-8)*7}{3+7} \right )\\\\= \left ( \dfrac{33-21}{10},\dfrac{15-56}{10} \right )\\\\=\left ( \dfrac{12}{10},\dfrac{-41}{10} \ right )$

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