The diagonals of rhombus wxyz intersect at point p. if wp = 4 and zp = 3, find the perimeter of the rhombus.

Check the picture below.

keep in mind that, in a rhombus, the diagonals meet a right-angles, thus P is at that junction, and that though slanted, all sides in a rhombus are the same length, so if WZ is that much, so are the other 3 sides.

and of course, the perimeter is all sides summed up.

You divide 112 by 14 and get 8 as the solution