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13.10.2020 •
Mathematics
The distribution of speeds along a certain stretch of highway has an mean of 76 mph
and a standard deviation of 7 mph.
What percentage of cars would be traveling slower than 55 mph?
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Ответ:
0.13%
Step-by-step explanation:
Given that :
Mean = 76mph
Standard deviation = 7 mph
Percentage of cars traveling slower than 55mph
Obtain the Zscore :
X = 55mph
Zscore = (X - mean) / standard deviation
Zscore = (55 - 76) / 7
Zscore = - 3
P(Z < - 3)
From the z table :
P(Z < - 3) = 0.0013
Hence, percentage of cars traveling slower than 55mph is (0.0013 * 100%) = 0.13%
Ответ:
x=2,-8
Step-by-step explanation:
x^2+6x-6=10
x^2+6x-16=0
(x+8)(x-2)= x^2-2x+8x-16=x^2+6x-16
x=2,-8