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dbailey6190
21.07.2019 •
Mathematics
The equation 3sinx+cos^2x=2 is solved below ! !
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Ответ:
3sin x+cos²x=2
3sin x+(1-sin²x)=2
-sin²x +3sin x=1
sin²x -3 sin x+1=0> up to here the procedure is correct
let
A=sin x
then
A²-3A+1=0
Group terms that contain the same variable, and move the constant to the opposite side of the equation
(A²-3A)=-1Complete the square. Remember to balance the equation by adding the same constants to each side.
(A²-3A+2.25)=-1+2.25
Rewrite as perfect squares
(A-1.5)²=1.25(+/-)(A-1.5)=1.12
first solution
(A-1.5)=1.12> A=1.12+1.5> A=2.62> sin x=2.62
second solution
-(A-1.5)=1.12> -A+1.5=1.12> A=1.5-1.12> A=0.38---> sin x=0.38
the answer is
the equation was factored incorrectly
Ответ:
equilateral- all sides the same
isosceles- 2 sides the same
scalene - none of the sides are the same.