Mathematics: The equation for the circle is: x^2 + y^2 +14x+10y−7=0 . what is the center of the circle?

The equation for the circle is: x^2 + y^2 +14x+10y−7=0

kiasiab17

12.03.2022

we are given

x^2+y^2 +14x+10y-7=0

Firstly , we can complete x square and y square

we can rearrange it

x^2+14x+y^2 +10y-7=0

x^2+14x+7^2+y^2 +10y+5^2-7=0+7^2+5^2

x^2+14x+7^2+y^2 +10y+5^2=0+7^2+5^2+7

(x+7)^2+(y+5)^2=0+7^2+5^2+7

(x+7)^2+(y+5)^2=81

we can also write it as

(x+7)^2+(y+5)^2=9^2

now, we can compare it with standard equation of circle

(x-h)^2+(y-k)^2=r^2

so, we will get

h=-7 , k=-5 , r=9

so,

center=(-7,-5)

radius=9 ................Answer

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kaylijocombs

20.02.2023

y=4,728,779,608,739,020,800

Step-by-step explanation: based on the values you have for m & b it would be...

y=4,200 x $2^{50}$

y=4,200 x 1,125,899,906,842,624

y=4,728,779,608,739,020,800

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