The equation is:
point k is between points j and l. if jk= x^2-4x, kl= 3x-2 and jl=28, find the lengths of jk and kl
basically x^2-x-2 and how to solve that

You would take x^2-4x+3x-2=28 
add common numbers x^2-x-2=28
set it equal to 0  x^2-x-30
use the quadratic formula x=1+-√1-4(1)(-30)÷2
Solve for x 1+-√131÷2
X÷≈6.223 
plug x into both equations for kl and jl and you will get lenghts that are ≈13.829 for Jk and ≈16.669 for KL

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Step-by-step explanation: