jpichardo2021
08.06.2021 •
Mathematics
The equation of a circle is (x+8)2+(y-5)2=14. What are the coordinates of the center of the circle?
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Ответ:
(-8,5)
Step-by-step explanation:
The standard form of the equation of a circle is expressed as;
(x-a)^2+(y-b)^2 = r^2 where;
(a, b) is the centre
r is the radius
Given the equation (x+8)^2+(y-5)^2=14.
Compare the two expressions
-a = +8
a = -8
Similarly;
-b = -5
b = 5
Hence the centre of the circle is at (-8,5)
Ответ: