The equation of line qr is y = negative 1 over 2x + 1. write an equation of a line perpendicular to line qr in slope-intercept form that contains point (5, 6).

Any perpendicular line has a negative reciprocal slope. So your slope would be 2. The. You would have the equation : y=2x+b. You would then replace the coordinate (5,6) with x and y on your line to solve for b. Your equation would be : y=2x-4

Step-by-step explanation:

Given the equation of line QR is

we have to find the equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

The slope-intercept form is

Compare general equation with given equation.

As we know the slope of perpendicular line of negative reciprocal of given line therefore, the slope of perpendicular to line QR is

The equation of line with slope m and passing through the point (x',y') is

Therefore, the equation of line with slope 2 and passing through the point (5, 6) is

which is required slope-intercept form of line perpendicular to line QR.

MON = 15°

LOM + MON = LON in measure, so
9x + 44 + 6x + 3 = 77
15x + 47 = 77
15x = 30
x = 2

MON = 6x + 3
= 6(2) + 3
= 12 + 3 = 15°