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22.07.2021 •
Mathematics
The equation of the line in the xy-plane that has slope 7/6 and passes through (9.-6) is
a. O 6x-7y+27 = 0
b. O 7x+6y-27 = 0
c. O 6x+7y-27=0
d. 0 6x+7 y+27 = 0
e. O -7x+6y+99 = 0
f.
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Ответ:
0 = 7x-6y -99
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 7/6x+b
Using the point
-6 = 7/6(9) +b
-6 = 7*3/2 +b
-6 = 21/2 +b
Subtract 21/2 from each side
-12/2 -21/2 = b
-33/2 = b
y= 7/6x -33/2
Multiply each side by 6
6y = 7x - 99
Subtract 6y from each side
0 = 7x-6y -99
Ответ: