The expression 4x^2-px-7 leaves a remainder of

Ответ:

bnnn

11.01.2022

The expression 4x^2-px-7 leaves a remainder of -2 when divided by (x-3). Then the value of p is 10.33

Solution:

Given the expression is 4x^2 - px - 7 leaves a remainder of -2 when divided by (x-3)

To find: value of p

x - 3 = 0

x = 3

Let g(x) = 4x^2 - px - 7

Hence we can say,

g(3) = -2

Substitute x = 3 in g(x) we get,

$g(3) = 4(3)^2 - p(3) - 7\\\\-2 = 4(3)^2 - p(3) - 7$

On solving we get,

-2 = 4(9) - 3p - 7

-2 = 36 - 3p - 7

3p = 36 - 7 + 2

3p = 31

$p = \frac{31}{3} = 10.33$

Thus the value of p is 10.33

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