The figure above shows a circle with center Cand radius 6. What is the sum of the areas of the two
shaded regions?
160
С​

Sum of the areas of two  shaded regions = 100 unit² (Approx.)

Step-by-step explanation:

Given:

Radius of circle = 6 units

Angle of one unshaded area = 160'

Find:

Sum of the areas of two  shaded regions

Computation:

Angle of one shaded area = 180' - 160'

Angle of one unshaded area = 20'

Sum of the areas of two  shaded regions = 2[θ/360][πr²]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(6)²]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(36)]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(36)]

Sum of the areas of two  shaded regions = [0.888][113.04]

Sum of the areas of two  shaded regions = 100.46

Sum of the areas of two  shaded regions = 100 unit² (Approx.)

B E F G

Step-by-step explanation:

Polygons are 2 dimensional shapes with straight edges (no curved edges). The shape needs to be closed up entirely to be a polygon. It cannot have any intersecting line segments

A can't be a polygon because the shape isn't closed up entirely

C can't be a polygon because it is a 3d shape

D can't be a polygon because it has curved edges.

H can't be a polygon because it isn't closed up (there are no line segments).

I can't be a polygon because polygons cannot have intersecting lines

J can't be a polygon because polygons cannot have intersecting lines

I hope this helps! If it does, a rate or brainliest would be much appreciated. :)