the figure below represents a play space that logan fenced in for his dog.
10 ft
- 12 ft2
logan is getting a second dog and wants to increase the length of the play
space by 3 feet and the width by 3 feet. what will be the difference in the area,
in square feet, between the original play space and the new play space?
show your work.

Difference in area = 75 ft²

Step-by-step explanation:

Case 1 (When logan had only  one dog):

length of the play space= ft

breadth of the play space= ft

we know that area of a rectangle is length times breadth (length x breadth)

therefore, area of the play space=

                                                      =

Case 2(When Logan had two dogs):

Given: Logan wants to increase the length of the play space by 3 feet  and width by 3 feet

⇒length of the play space= ft= ft

breadth of the play space= ft= ft

we know that area of a rectangle is length times breadth (length x breadth)

therefore, area of the play space=

                                                      =

Therefore difference in the area of play space =

                                                                                =75 ft²